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For the simplified representation of an enzyme-catalyzed reaction shown below, the statement "ES is in steady-state" means that:E + S (k1,k-1) > ES (k2, k-2) > E + PA) k2 is very slow.B) k1= k2.C) k1= k-1.D) k1[E][S] = k-1[ES] + k2[ES].E) k1[E][S] = k-1[ES].
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