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比Shortest Word Distance I 多了一个word1.equals(word2)的条件 for (int i = 0; i < words.length; i++) { if (words[i].equals(word1) || words[i].equals(word2)) { if (index != -1 && (word1.equals(word2) || !words[index].equals(words[i]))) { min = Math.min(i - index, min); } index = i; } }
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