Back to Questions
Want to know:
Alexia ran three laps around her neighborhood. Each lap is 1 3/8 miles. Which is the best estimate of the number of miles that Alexia ran?
Get a detailed, AI-powered explanation for this question and thousands more on StudyFetch.
Get the Answer for FreeHow StudyFetch Helps You Master This Topic
AI-Powered Answers
Get instant, detailed explanations powered by AI that understands your course material.
Deep Understanding
Go beyond surface-level answers with step-by-step breakdowns and examples.
Personalized Learning
Sparky adapts to your learning style and helps you connect ideas.
Practice & Test
Turn any question into flashcards, quizzes, and practice tests to solidify your knowledge.
Explore More Questions
- donne la formule pour diviser des fractions (avec les lettres a, b, c et d)
- Would the Manager like to open the discussion, and tell us a little bit about this case ?
- Sorted two pointer two sum with a outter loopThe key is to avoid duplicates, in the outer loop when num[i] == num[i - 1], continue, so you only use the first element of duplicated element. In the inner loop also, i and j need to avoid duplicates using a while loop for (int i = 0; i < n; i++) { if (i != 0 && numbers[i] == numbers[i - 1]) { continue; } int j = i + 1, k = n - 1; while (j < k) { if (numbers[j] + numbers[k] > -numbers[i]) { int number = numbers[k]; while (k > j && numbers[k] == number) { k--; } } else if (numbers[j] + numbers[k] < -numbers[i]) { int number = numbers[j]; while (j < k && numbers[j] == number) { j++; } } else { ArrayList<Integer> tmp = new ArrayList<Integer>(Arrays.asList(numbers[i], numbers[j], numbers[k])); Collections.sort(tmp); res.add(tmp); int number = numbers[k]; while (k > j && numbers[k] == number) { k--; } number = numbers[j]; while (j < k && numbers[j] == number) { j++; } } }